我建立了个数据库： CREATE TABLE `product` ( `p_no` CHAR( 10 ) NOT NULL , `p_name` CHAR( 50 ) NOT NULL , `unit` CHAR( 10 ) NOT NULL , `price` CHAR( 20 ) NOT NULL , `place` CHAR( 100 ) , PRIMARY KEY ( `p_no` ) ) TYPE = MYISAM ; 然后建立了一个test.php <?php $db=mysql_connect("sky","root"); mysql_select_db("bc_db",$db); $result=mysql_query("SELECT*FROM product",$db); printf("产品编号：%s
\n",mysql_result($result,0,"p_no")); printf("产品名称: %s
\n",mysql_result($result,0,"p_name")); printf("单价:%s
\n" ,mysql_result($result,0,"price")); printf("产地:%s
\n", mysql_result($result,0,"place")); ?> 在APACHE下运行出现下列错误提示： Warning: Unable to jump to row 0 on MySQL result index 2 in c:\apache\htdocs\test1.php on line 5 产品编号： Warning: Unable to jump to row 0 on MySQL result index 2 in c:\apache\htdocs\test1.php on line 6 产品名称: Warning: Unable to jump to row 0 on MySQL result index 2 in c:\apache\htdocs\test1.php on line 7 单价: Warning: Unable to jump to row 0 on MySQL result index 2 in c:\apache\htdocs\test1.php on line 8 产地: 我的环境是：apache+mysql+php 请问是什么原因，在线等待，谢谢！