麻辣堂|资源主站|开发论坛|在线手册
首页 Apache Linux Java MySQL 注册帮助 
PHP项目开发组是PHP开发资源网于2007组年建成立的项目开发团队,目前核心开发成员有27人, 项目协作成员8名.下设7个开发组,主要承接大/中型网站项目开发任务。

    由于开发任务较多,人员比较紧张,现面向社会招聘全职或者兼职开发人员,不管你是在校大学生,还是全职开发人员,以及SOHO都可以联系本站,我们可以长期合作,并为您带来丰厚的报酬。
  您现在的位置:PHP开发资源网 > 麻辣堂 > 详细资料
待解决
请各位大虾帮我把这段程序补完整
悬赏分:20 - 2007年08月14日

后页的分页我不会写了,谁能帮我补充完整呢 [PHP] if ($HTTP_POST_VARS['action']=="search"){ mysql_connect($dbhost,$dbuser,$dbpasswd) or die ("数据库连接失败"); if (($year!="") and ($month!="") and ($day!="")): $riqi = $year."-".$month."-".$day; $grtime = "and riqi = '$riqi'"; else: $grtime =""; endif; if ($age!=""): $grage = " and age like '%$age%'"; else: $grage =""; endif; if ($sex!=""): $grsex = " and sex like '%$sex%'"; else: $grsex =""; endif; if ($nation!=""): $grnation = " and nation like '%$nation%'"; else: $grnation =""; endif; if ($culture!=""): $grculture = " and culture like '%$culture%'"; else: $grculture =""; endif; if ($job!=""): $grjob = " and job like '%$job%'"; else: $grjob =""; endif; if ($degree!=""): $grdegree = " and degree like '%$degree%'"; else: $grdegree =""; endif; if ($study!=""): $grstudy = " and study like '%$study%'"; else: $grstudy =""; endif; if ($level!=""): $grlevel = " and level like '%$level%'"; else: $grlevel =""; endif; $searchgr = " WHERE 1 ".$grtime."".$grage."".$grsex."".$grnation."".$grculture."".$grjob."".$grdegree."".$grstudy."".$grlevel.""; mysql_connect($dbhost,$dbuser,$dbpasswd) or die ("数据库连接失败"); $sql = "SELECT COUNT(*) AS rcnt FROM $nxdzkj_grzp $searchgr ORDER BY id DESC"; $result = mysql_db_query($dbname, $sql); $row = mysql_fetch_array($result); $num = $row[rcnt]; if (empty($setid)): $setid = 0; endif; if ($num =="0"){ echo ""; echo "未找到任何记录"; echo ""; }else{ $sql = "SELECT * FROM $nxdzkj_grzp $searchgr ORDER BY id DESC LIMIT $setid, $list_num"; $result = mysql_db_query($dbname, $sql); while ($row=mysql_fetch_array($result)) { echo ""; echo "$row[id]"; echo "$row[name]"; echo "$row[sex]"; echo "$row[nation]"; echo ""; if ($row[job]=="0"){ echo "不限"; }else{ echo $row[job]; } echo ""; echo ""; if ($row[culture]=="0"){ echo "不限"; }else{ echo $row[culture]; } echo ""; echo "$row[study]"; echo "$row[demand]"; echo ""; } // while } } [/PHP] :confused: :confused: :confused: :confused:

提问者:lee-free   08-14 11:11
答复
路过。。。顺便帮顶:)
回答者:玉米づ冰冻可乐 - 瓦岗村民 8-22 09:10
我也来回答:
不管你有没有帮助我们,瓦岗寨8万村民将感谢你。。。。。

为防止灌水,您需要计算一道数学题: 答案:
36 + 21 = ? 请将计算结果填在上面

 
[]
©2007 PhpRes.COM