不好意思我是回复这个主题的：
http://www.phpx.com/happy/showthread.php?s=&threadid=36503

是的！
不信你看看！

$today=date("Y-m-d H:i:s");
$theday=date("Y-m-d H:i:s",mktime(1,2,3,12,1,2003));

echo $theday-$today;

if(($theday-$today)>3) echo "ok"; else echo "no";


显示为0no



[PHP]$today=date("Y-m-d H:i:s");
$theday=date("Y-m-d H:i:s",mktime(1,2,3,12,1,2003));
echo $theday-$today;
if(($theday-$today)>3) echo "ok"; else echo "no";

[/PHP]