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function doSomething( $formData )
{
$objResponse = new xajaxResponse();
$str="";
foreach($formData as $key=>$value)
if (empty($str))
$str.=$key."='".$value."'";
else
$str.=",".$key."='".$value."'";
//$str="form data is ".implode(",",$formData);
//$objResponse->addAlert(print_r($formData));
$objResponse->addAssign("result", "innerHTML", $str );
return $objResponse->getXML();
}
function hb()
{
$objResponse = new xajaxResponse();
$objResponse->addScript("xajax_doSomething(xajax.getFormValues('someForm'));");
return $objResponse->getXML();
}
像这个例子,为什么我不能用 在 doSomething( ) 内部调用表单内容啊??如:
function doSomething( )
{
$formData=xajax.getFormValues('someForm'); // ******调用******//
$objResponse = new xajaxResponse();
$str="";
foreach($formData as $key=>$value)
if (empty($str))
$str.=$key."='".$value."'";
else
$str.=",".$key."='".$value."'";
//$str="form data is ".implode(",",$formData);
//$objResponse->addAlert(print_r($formData));
$objResponse->addAssign("result", "innerHTML", $str );
return $objResponse->getXML();
}
请指教???????????
[ 本帖最后由 panglongphp 于 2006-6-28 10:33 AM 编辑 ]
提问者:panglongphp 08-22 08:08
答复

