今天在学AJAX的POST方法

这是我找的一个例子

很奇怪.的是........ 如果我把JS的代码直接放在 HTML 代码里面 , AJAX 能出来效果

但是如果我把 JS 代码 包含到一个文件里面再由HTML页面去调用他的话,就会提示缺少对象



我很纳闷...是完全一样的代码,怎么做一个引用就会出错~~~~~~~

希望大哥们 有时间的就帮忙看看


谢谢!!!!

压缩包里面 一个是成功了的AJAX代码,另一个就是引用而报错的....



1.PHP 的代码
[php]

<?php


sleep(2);
echo $firstName = $_POST["firstName"]."成功拉";
//String lastName = request.getParameter("lastName");
//String gender = request.getParameter("gender");
//String country = request.getParameter("country");
//out.println("firstName:"+firstName);
//out.println("lastName:"+lastName);
//out.println("gender:"+gender);
//out.println("country:"+country);

?>

[/php]






1.HTML的代码
[php]






<script language="JavaScript" src="1.js">

/*
var http_request = false;

function send_request(queryString)
{
if(window.XMLHttpRequest)
{
http_request = new XMLHttpRequest();
}
else if(window.ActiveXObject)
{
http_request = new ActiveXObject("Microsoft.XMLHTTP");
}
if(!http_request)
{
window.alert("创建实例失败...");
return false;
}
http_request.onreadystatechange = processRequest;
http_request.open("POST","1.php",true);
http_request.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=GB2312");
http_request.send(queryString);
}

function processRequest()
{

msg=document.getElementById("fanhuei");

if(http_request.readyState == 4)
{
if(http_request.status == 200)
{
msg.innerHTML=http_request.responseText;
}
else
{
alert("请求的页面异常");
}
}
else
{
msg.innerHTML="数据下载中...HOHO";
}
}

function userCheck()
{
queryString = "firstName="+document.form1.firstname.value+"&"+"lastName="+document.form1.lastname.value+"&"+"gender="+document.form1.gender.value+"&"+"country="+document.form1.country.value;
send_request(queryString);
}
*/


</script>

直接调用JS代码.rar

通过引用调用JS代码.rar